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How to construct a circle circumscribed around a triangle.

Published: 2011/08/29

Channel: Leo Screen

Circumscribed and Inscribed Circles and Polygons

Published: 2010/05/13

Channel: Brightstorm

Construct a Circle Circumscribed about a Triangle

Published: 2012/02/23

Channel: kelly castaneda

C16--Construct a Circumscribed Circle Around a Triangle

Published: 2014/04/02

Channel: Glenn Olson

Area of a Triangle and Radius of its Circumscribed Circle

Published: 2015/06/10

Channel: Mr. T's Math Videos

Constructing circumscribing circle | Geometric constructions | Geometry | Khan Academy

Published: 2015/07/17

Channel: Khan Academy

10.7 Inscribed and Circumscribed Polygons (Lesson)

Published: 2012/03/05

Channel: AutenMath

Measure of circumscribed angle | Circles | Geometry | Khan Academy

Published: 2013/12/09

Channel: Khan Academy

Circles 2B perimeter of circumscribed polygons

Published: 2014/10/21

Channel: apethan

Circumscribed square about a circle

Published: 2016/01/21

Channel: CBSE

Construct Circumcenter and a Circle that Circumscribes the Triangle

Published: 2012/12/10

Channel: Andrew Yep

What is inscribed and circumscribed in geometry?

Published: 2012/08/13

Channel: MooMoo Math and Science

Circumscribed regular pentagon about a circle

Published: 2016/02/01

Channel: CBSE

How to Draw Inscribed and Circumscribed Circles

Published: 2009/12/18

Channel: AlexPleaseHelpDotCom

how to derive the area of a polygon circumscribed around a circle

Published: 2014/11/03

Channel: Olivia Siemens

Circles: Circumscribed Angles

Published: 2014/11/16

Channel: FerranteMath

Constructing an equilateral triangle inside a given circle

Published: 2014/04/13

Channel: Michael Hartley

How to draw a circle circumscribed around a triangle

Published: 2017/03/20

Channel: Jacob Lopez

Area of inscribed equilateral triangle (some basic trig used) | Circles | Geometry | Khan Academy

Published: 2010/03/18

Channel: Khan Academy

Optimization Minimum Area of Isosceles Triangle Circumscribed a Circle Calculus MCV

Published: 2016/03/17

Channel: Anil Kumar

Constructing a Circumscribed Circle

Published: 2017/04/07

Channel: Brittany Wilhelm

Circumscribed hexagon

Published: 2016/01/01

Channel: CBSE

Circumscribed Circle Definition-Inscribed Circle Definition

Published: 2015/12/29

Channel: MooMoo Math and Science

How to Construct a Circumscribed Circle of an Obtuse Triang... : Math Conversions, Equations & More

Published: 2014/01/16

Channel: eHowEducation

Construct the circumscribed circle of a triangle.

Published: 2011/07/12

Channel: fahrenba

Module 27 Constructions: Perpendicular Bisector, Circumcenter, and Circumscribed Circle

Published: 2013/10/04

Channel: Duncan Baumgart

12 Circumscribed Circle

Published: 2016/10/01

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Circumscribed equilateral triangle about a circle

Published: 2016/01/21

Channel: CBSE

Constructing a circumscribed circle for a triangle

Published: 2015/08/21

Channel: MrLeSaulnierMath

Construction #10 - Circumscribe a Circle Around a Triangle

Published: 2013/04/17

Channel: NathanaelandSara Bresson

Consruct a Circumscribed circle with Geogebra

Published: 2014/11/14

Channel: Penelope Templeton

V15. Right Triangle & Circumscribed Circle. Chord & Radius

Published: 2013/12/05

Channel: Eugene Toronto Russian School Geometry

Geometry Similar Triangles incribed circumscribed Circle

Published: 2012/05/14

Channel: charlie Lindelof

Inscribed And Circumscribed | Geometry | Chegg Tutors

Published: 2016/03/11

Channel: Chegg

Video 6Q1 Constructing a Circumscribed Circle

Published: 2015/03/24

Channel: Erin Pollock

Circumscribed Circle.avi

Published: 2011/01/06

Channel: conwaymcps

Square - given circumscribed circle

Published: 2016/05/19

Channel: Bishop Lance

Circumscribed Circle (1.5)

Published: 2012/09/12

Channel: Jeff Nelson

Ratio of Circumscribed Square to Inscribed Square

Published: 2015/10/22

Channel: Ms. Hearn

Geometry 13.1j - Constructing the Circumcircle of a Right Triangle

Published: 2013/12/30

Channel: Derek Owens

Constructing a regular hexagon with a ruler and compass, inside a given circle

Published: 2014/04/14

Channel: Michael Hartley

circumscribed circle

Published: 2011/10/17

Channel: eze212121

Inscribed and Circumscribed Triangles and Quadrilaterals

Published: 2016/04/18

Channel: Suzann Mitchell

Equilateral triangle - given circumscribed circle

Published: 2016/05/14

Channel: Bishop Lance

Regular pentagon - given circumscribed circle

Published: 2016/05/26

Channel: Bishop Lance

Constructing a square with a ruler and compass, inside a given circle

Published: 2014/04/14

Channel: Michael Hartley

Circumscribed Circles and Polygons by Duong Nguyen

Published: 2016/10/31

Channel: Ryan Card

Constructing the Circumcenter and Circumscribed Circle

Published: 2012/09/27

Channel: missteacher9229

Circle Inscribed in an Equilateral Triangle

Published: 2011/08/15

Channel: gmathacks

32 - Construct a Circumscribed Circle Around a Triangle

Published: 2016/08/20

Channel: VIPArts Department

(Redirected from Circumcircle)

In geometry, the **circumscribed circle** or **circumcircle** of a polygon is a circle which passes through all the vertices of the polygon. The center of this circle is called the **circumcenter** and its radius is called the **circumradius**.

A polygon which has a circumscribed circle is called a **cyclic polygon** (sometimes a **concyclic polygon**, because the vertices are concyclic). All regular simple polygons, all isosceles trapezoids, all triangles and all rectangles are cyclic.

A related notion is the one of a minimum bounding circle, which is the smallest circle that completely contains the polygon within it. Not every polygon has a circumscribed circle, as the vertices of a polygon do not need to all lie on a circle, but every polygon has a unique minimum bounding circle, which may be constructed by a linear time algorithm.^{[2]} Even if a polygon has a circumscribed circle, it may not coincide with its minimum bounding circle; for example, for an obtuse triangle, the minimum bounding circle has the longest side as diameter and does not pass through the opposite vertex.

- 1 Triangles
- 2 Cyclic quadrilaterals
- 3 Cyclic
*n*-gons - 4 See also
- 5 Notes
- 6 References
- 7 External links

All triangles are cyclic; i.e., every triangle has a circumscribed circle.

This can be proven on the grounds that the general equation for a circle with center (*a*, *b*) and radius *r* in the Cartesian coordinate system is

Since this equation has three parameters (*a*, *b*, *r*) only three points' coordinate pairs are required to determine the equation of a circle. Since a triangle is defined by its three vertices, and exactly three points are required to determine a circle, every triangle can be circumscribed.

The circumcenter of a triangle can be constructed by drawing any two of the three perpendicular bisectors. The center is the point where the perpendicular bisectors intersect, and the radius is the length to any of the three vertices.

This is because the circumcenter is equidistant from any pair of the triangle's vertices, and all points on the perpendicular bisectors are equidistant from two of the vertices of the triangle.

An alternate method to determine the circumcenter is to draw any two lines each one departing from one of the vertices at an angle with the common side, the common angle of departure being 90° minus the angle of the opposite vertex. (In the case of the opposite angle being obtuse, drawing a line at a negative angle means going outside the triangle.)

In coastal navigation, a triangle's circumcircle is sometimes used as a way of obtaining a position line using a sextant when no compass is available. The horizontal angle between two landmarks defines the circumcircle upon which the observer lies.

In the Euclidean plane, it is possible to give explicitly an equation of the circumcircle in terms of the Cartesian coordinates of the vertices of the inscribed triangle. Suppose that

are the coordinates of points *A*, *B*, and *C*. The circumcircle is then the locus of points **v** = (*v*_{x},*v*_{y}) in the Cartesian plane satisfying the equations

guaranteeing that the points **A**, **B**, **C**, and **v** are all the same distance *r* from the common center *u* of the circle. Using the polarization identity, these equations reduce to the condition that the matrix

has a nonzero kernel. Thus the circumcircle may alternatively be described as the locus of zeros of the determinant of this matrix:

Using cofactor expansion, let

we then have a|**v**|^{2} − 2**Sv** − *b* = 0 and, assuming the three points were not in a line (otherwise the circumcircle is that line that can also be seen as a generalized circle with S at infinity), |**v** − **S**/*a*|^{2} = *b*/*a* + |**S**|^{2}/*a*^{2}, giving the circumcenter **S**/*a* and the circumradius √(*b*/*a* + |**S**|^{2}/*a*^{2}). A similar approach allows one to deduce the equation of the circumsphere of a tetrahedron.

A unit vector perpendicular to the plane containing the circle is given by

Hence, given the radius, *r*, center, *P _{c}*, a point on the circle,

An equation for the circumcircle in trilinear coordinates *x* : *y* : *z* is^{[1]}^{:p. 199} *a*/*x* + *b*/*y* + *c*/*z* = 0. An equation for the circumcircle in barycentric coordinates *x* : *y* : *z* is *a*^{2}/*x* + *b*^{2}/*y* + *c*^{2}/*z* = 0.

The isogonal conjugate of the circumcircle is the line at infinity, given in trilinear coordinates by *ax* + *by* + *cz* = 0 and in barycentric coordinates by *x* + *y* + *z* = 0.

Additionally, the circumcircle of a triangle embedded in *d* dimensions can be found using a generalized method. Let **A**, **B**, and **C** be *d*-dimensional points, which form the vertices of a triangle. We start by transposing the system to place **C** at the origin:

The circumradius, *r*, is then

where *θ* is the interior angle between **a** and **b**. The circumcenter, *p*_{0}, is given by

This formula only works in three dimensions as the cross product is not defined in other dimensions, but it can be generalized to the other dimensions by replacing the cross products with following identities:

The Cartesian coordinates of the circumcenter are

with

Without loss of generality this can be expressed in a simplified form after translation of the vertex *A* to the origin of the Cartesian coordinate systems, i.e., when *A*′ = *A* − *A* = (*A*′_{x},*A*′_{y}) = (0,0). In this case, the coordinates of the vertices *B*′ = *B* − *A* and *C*′ = *C* − *A* represent the vectors from vertex *A*′ to these vertices. Observe that this trivial translation is possible for all triangles and the circumcenter of the triangle *A*′*B*′*C*′ follow as

with

Due to the translation of vertex *A* to the origin, the circumradius *r* can be computed as

and the actual circumcenter of *ABC* follows as

The circumcenter has trilinear coordinates^{[1]}^{:p.19}

- cos
*α*: cos*β*: cos*γ*

where *α*, *β*, *γ* are the angles of the triangle.

In terms of the side lengths *a, b, c*, the trilinears are^{[2]}

The circumcenter has barycentric coordinates

^{[3]}

where *a*, *b*, *c* are edge lengths (*BC*, *CA*, *AB* respectively) of the triangle.

In terms of the triangle's angles the barycentric coordinates of the circumcenter are^{[2]}

Since the Cartesian coordinates of any point are a weighted average of those of the vertices, with the weights being the point's barycentric coordinates normalized to sum to unity, the circumcenter vector can be written as

Here *U* is the vector of the circumcenter and *A, B, C* are the vertex vectors. The divisor here equals 16*S* ^{2} where *S* is the area of the triangle.

In Euclidean space, there is a unique circle passing through any given three non-collinear points *P*_{1}, *P*_{2}, and *P*_{3}. Using Cartesian coordinates to represent these points as spatial vectors, it is possible to use the dot product and cross product to calculate the radius and center of the circle. Let

Then the radius of the circle is given by

The center of the circle is given by the linear combination

where

The circumcenter's position depends on the type of triangle:

- If and only if a triangle is acute (all angles smaller than a right angle), the circumcenter lies inside the triangle.
- If and only if it is obtuse (has one angle bigger than a right angle), the circumcenter lies outside the triangle.
- If and only if it is a right triangle, the circumcenter lies at the center of the hypotenuse. This is one form of Thales' theorem.

These locational features can be seen by considering the trilinear or barycentric coordinates given above for the circumcenter: all three coordinates are positive for any interior point, at least one coordinate is negative for any exterior point, and one coordinate is zero and two are positive for a non-vertex point on a side of the triangle.

The angles which the circumscribed circle forms with the sides of the triangle coincide with angles at which sides meet each other. The side opposite angle *α* meets the circle twice: once at each end; in each case at angle *α* (similarly for the other two angles). This is due to the **alternate segment theorem**, which states that the angle between the tangent and chord equals the angle in the alternate segment.

In this section, the vertex angles are labeled *A*, *B*, *C* and all coordinates are trilinear coordinates:

- Steiner point =
*bc*/ (*b*^{2}−*c*^{2}) :*ca*/ (*c*^{2}−*a*^{2}) :*ab*/ (*a*^{2}−*b*^{2}) = the nonvertex point of intersection of the circumcircle with the Steiner ellipse. (The Steiner ellipse, with center = centroid(*ABC*), is the ellipse of least area that passes through*A*,*B*, and*C*. An equation for this ellipse is 1/(*ax*) + 1/(*by*) + 1/(*cz*) = 0.) - Tarry point = sec (
*A*+ ω) : sec (*B*+ ω) : sec (*C*+ ω) = antipode of the Steiner point - Focus of the Kiepert parabola = csc (
*B*−*C*) : csc (*C*−*A*) : csc (*A*−*B*).

The diameter of the circumcircle, called the **circumdiameter** and equal to twice the **circumradius**, can be computed as the length of any side of the triangle divided by the sine of the opposite angle:

As a consequence of the law of sines, it does not matter which side and opposite angle are taken: the result will be the same.

The diameter of the circumcircle can also be expressed as

where *a*, *b*, *c* are the lengths of the sides of the triangle and *s* = (*a* + *b* + *c*)/2 is the semiperimeter. The expression above is the area of the triangle, by Heron's formula.^{[3]} Trigometric expressions for the diameter of the circumcircle include^{[4]}^{:p.379}

The triangle's nine-point circle has half the diameter of the circumcircle.

In any given triangle, the circumcenter is always collinear with the centroid and orthocenter. The line that passes through all of them is known as the Euler line.

The isogonal conjugate of the circumcenter is the orthocenter.

The useful minimum bounding circle of three points is defined either by the circumcircle (where three points are on the minimum bounding circle) or by the two points of the longest side of the triangle (where the two points define a diameter of the circle). It is common to confuse the minimum bounding circle with the circumcircle.

The circumcircle of three collinear points is the line on which the three points lie, often referred to as a *circle of infinite radius*. Nearly collinear points often lead to numerical instability in computation of the circumcircle.

Circumcircles of triangles have an intimate relationship with the Delaunay triangulation of a set of points.

By Euler's theorem in geometry, the distance between the circumcenter *O* and the incenter *I* is

where *r* is the incircle radius and *R* is the circumcircle radius; hence the circumradius is at least twice the inradius (Euler's triangle inequality), with equality only in the equilateral case.^{[5]}^{[6]}^{:p. 198}

The distance between *O* and the orthocenter *H* is^{[7]}^{[8]}^{:p. 449}

For centroid *G* and nine-point center *N* we have

The product of the incircle radius and the circumcircle radius of a triangle with sides *a*, *b*, and *c* is^{[9]}^{: p. 189, #298(d)}

With circumradius *R*, sides *a*, *b*, *c*, and medians *m*_{a}, *m*_{b}, and *m*_{c}, we have^{[10]}^{:p.289–290}

If median *m*, altitude *h*, and internal bisector *t* all emanate from the same vertex of a triangle with circumradius *R*, then^{[11]}^{:p.122,#96}

Carnot's theorem states that the sum of the distances from the circumcenter to the three sides equals the sum of the circumradius and the inradius.^{[11]}^{:p.83} Here a segment's length is considered to be negative if and only if the segment lies entirely outside the triangle.

If a triangle has two particular circles as its circumcircle and incircle, there exist an infinite number of other triangles with the same circumcircle and incircle, with any point on the circumcircle as a vertex. (This is the *n*=3 case of Poncelet's porism). A necessary and sufficient condition for such triangles to exist is the above equality ^{[9]}^{:p. 188}

Quadrilaterals that can be circumscribed have particular properties including the fact that opposite angles are supplementary angles (adding up to 180° or π radians).

For a cyclic polygon with an odd number of sides, all angles are equal if and only if the polygon is regular. A cyclic polygon with an even number of sides has all angles equal if and only if the alternate sides are equal (that is, sides 1, 3, 5, ... are equal, and sides 2, 4, 6, ... are equal).^{[12]}

A cyclic pentagon with rational sides and area is known as a Robbins pentagon; in all known cases, its diagonals also have rational lengths.^{[13]}

In any cyclic *n*-gon with even *n*, the sum of one set of alternate angles (the first, third, fifth, etc.) equals the sum of the other set of alternate angles. This can be proven by induction from the *n*=4 case, in each case replacing a side with three more sides and noting that these three new sides together with the old side form a quadrilateral which itself has this property; the alternate angles of the latter quadrilateral represent the additions to the alternate angle sums of the previous *n*-gon.

Let one *n*-gon be inscribed in a circle, and let another *n*-gon be tangential to that circle at the vertices of the first *n*-gon. Then from any point *P* on the circle, the product of the perpendicular distances from *P* to the sides of the first *n*-gon equals the product of the perpendicular distances from *P* to the sides of the second *n*-gon.^{[9]}^{:p. 72}

Let a cyclic *n*-gon have vertices *A*_{1} , ..., *A*_{n} on the unit circle. Then for any point *M* on the minor arc *A*_{1}*A*_{n}, the distances from *M* to the vertices satisfy^{[14]}^{:p.190,#332.10}

Any regular polygon is cyclic. Consider a unit circle, then circumscribe a regular triangle such that each side touches the circle. Circumscribe a circle, then circumscribe a square. Again circumscribe a circle, then circumscribe a regular 5-gon, and so on. The radii of the circumscribed circles converge to the so-called *polygon circumscribing constant*

(sequence A051762 in the OEIS). The reciprocal of this constant is the Kepler–Bouwkamp constant.

- Inscribed circle
- Jung's theorem, an inequality relating the diameter of a point set to the radius of its minimum bounding circle
- Lester's theorem
- Circumscribed sphere
- Circumgon
- Triangle center
- Japanese theorem for cyclic quadrilaterals
- Japanese theorem for cyclic polygons
- Kosnita theorem

- ^
^{a}^{b}Whitworth, William Allen.*Trilinear Coordinates and Other Methods of Modern Analytical Geometry of Two Dimensions*, Forgotten Books, 2012 (orig. Deighton, Bell, and Co., 1866). http://www.forgottenbooks.com/search?q=Trilinear+coordinates&t=books - ^
^{a}^{b}Clark Kimberling's Encyclopedia of Triangles "Archived copy". Archived from the original on 2012-04-19. Retrieved 2012-06-02. **^**Wolfram page on barycentric coordinates**^**Dörrie, Heinrich,*100 Great Problems of Elementary Mathematics*, Dover, 1965.**^**Nelson, Roger, "Euler's triangle inequality via proof without words,"*Mathematics Magazine*81(1), February 2008, 58-61.**^**Dragutin Svrtan and Darko Veljan, "Non-Euclidean versions of some classical triangle inequalities",*Forum Geometricorum*12 (2012), 197–209. http://forumgeom.fau.edu/FG2012volume12/FG201217index.html**^**Marie-Nicole Gras, "Distances between the circumcenter of the extouch triangle and the classical centers",*Forum Geometricorum*14 (2014), 51-61. http://forumgeom.fau.edu/FG2014volume14/FG201405index.html**^**Smith, Geoff, and Leversha, Gerry, "Euler and triangle geometry",*Mathematical Gazette*91, November 2007, 436–452.- ^
^{a}^{b}^{c}Johnson, Roger A.,*Advanced Euclidean Geometry*, Dover, 2007 (orig. 1929). **^**Posamentier, Alfred S., and Lehmann, Ingmar.*The Secrets of Triangles*, Prometheus Books, 2012.- ^
^{a}^{b}Altshiller-Court, Nathan,*College Geometry*, Dover, 2007. **^**De Villiers, Michael. "Equiangular cyclic and equilateral circumscribed polygons,"*Mathematical Gazette*95, March 2011, 102-107.**^**Buchholz, Ralph H.; MacDougall, James A. (2008), "Cyclic polygons with rational sides and area",*Journal of Number Theory*,**128**(1): 17–48, MR 2382768, doi:10.1016/j.jnt.2007.05.005.**^***Inequalities proposed in “Crux Mathematicorum”*, [1].

- Coxeter, H.S.M. (1969). "Chapter 1".
*Introduction to geometry*. Wiley. pp. 12–13. ISBN 0-471-50458-0. - Megiddo, N. (1983). "Linear-time algorithms for linear programming in
**R**^{3}and related problems".*SIAM Journal on Computing*.**12**(4): 759–776. doi:10.1137/0212052. - Kimberling, Clark (1998). "Triangle centers and central triangles".
*Congressus Numerantium*.**129**: i–xxv, 1–295. - Pedoe, Dan (1988) [1970].
*Geometry: a comprehensive course*. Dover. ISBN 0-486-65812-0.

- Derivation of formula for radius of circumcircle of triangle at Mathalino.com
- Semi-regular angle-gons and side-gons: respective generalizations of rectangles and rhombi at Dynamic Geometry Sketches, interactive dynamic geometry sketch.

- Triangle circumcircle and circumcenter With interactive animation
- An interactive Java applet for the circumcenter

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