A Colpitts oscillator, invented in 1918 by American engineer Edwin H. Colpitts,^{[1]} is one of a number of designs for LC oscillators, electronic oscillators that use a combination of inductors (L) and capacitors (C) to produce an oscillation at a certain frequency. The distinguishing feature of the Colpitts oscillator is that the feedback for the active device is taken from a voltage divider made of two capacitors in series across the inductor.^{[2]}^{[3]}^{[4]}^{[5]}
The Colpitts circuit, like other LC oscillators, consists of a gain device (such as a bipolar junction transistor, field effect transistor, operational amplifier, or vacuum tube) with its output connected to its input in a feedback loop containing a parallel LC circuit (tuned circuit) which functions as a bandpass filter to set the frequency of oscillation.
A Colpitts oscillator is the electrical dual of a Hartley oscillator, where the feedback signal is taken from an "inductive" voltage divider consisting of two coils in series (or a tapped coil). Fig. 1 shows the commonbase Colpitts circuit. L and the series combination of C_{1} and C_{2} form the parallel resonant tank circuit which determines the frequency of the oscillator. The voltage across C_{2} is applied to the baseemitter junction of the transistor, as feedback to create oscillations. Fig. 2 shows the commoncollector version. Here the voltage across C_{1} provides feedback. The frequency of oscillation is approximately the resonant frequency of the LC circuit, which is the series combination of the two capacitors in parallel with the inductor
The actual frequency of oscillation will be slightly lower due to junction capacitances and resistive loading of the transistor.
As with any oscillator, the amplification of the active component should be marginally larger than the attenuation of the capacitive voltage divider, to obtain stable operation. Thus, a Colpitts oscillator used as a variable frequency oscillator (VFO) performs best when a variable inductance is used for tuning, as opposed to tuning one of the two capacitors. If tuning by variable capacitor is needed, it should be done via a third capacitor connected in parallel to the inductor (or in series as in the Clapp oscillator).
This section requires expansion with: Additional practical information regarding base biasing. (August 2014) 
Fig. 3 shows a working example with component values. Instead of bipolar junction transistors, other active components such as field effect transistors or vacuum tubes, capable of producing gain at the desired frequency, could be used.
The capacitor at the base provides an AC path to ground for parasitic inductances that could lead to unwanted resonance at undesired frequencies.^{[6]} Selection of the base's biasing resistors is not trivial. Periodic oscillation starts for a critical bias current and with the variation of the bias current to a higher value chaotic oscillations are observed ^{[7]}
This section may require cleanup to meet Wikipedia's quality standards. (April 2008) 
One method of oscillator analysis is to determine the input impedance of an input port neglecting any reactive components. If the impedance yields a negative resistance term, oscillation is possible. This method will be used here to determine conditions of oscillation and the frequency of oscillation.
An ideal model is shown to the right. This configuration models the common collector circuit in the section above. For initial analysis, parasitic elements and device nonlinearities will be ignored. These terms can be included later in a more rigorous analysis. Even with these approximations, acceptable comparison with experimental results is possible.
Ignoring the inductor, the input impedance at the base can be written as
Where is the input voltage and is the input current. The voltage is given by
Where is the impedance of . The current flowing into is , which is the sum of two currents:
Where is the current supplied by the transistor. is a dependent current source given by
Where is the transconductance of the transistor. The input current is given by
Where is the impedance of . Solving for and substituting above yields
The input impedance appears as the two capacitors in series with an interesting term, which is proportional to the product of the two impedances:
If and are complex and of the same sign, will be a negative resistance. If the impedances for and are substituted, is
If an inductor is connected to the input, the circuit will oscillate if the magnitude of the negative resistance is greater than the resistance of the inductor and any stray elements. The frequency of oscillation is as given in the previous section.
For the example oscillator above, the emitter current is roughly 1 mA. The transconductance is roughly 40 mS. Given all other values, the input resistance is roughly
This value should be sufficient to overcome any positive resistance in the circuit. By inspection, oscillation is more likely for larger values of transconductance and smaller values of capacitance. A more complicated analysis of the commonbase oscillator reveals that a low frequency amplifier voltage gain must be at least four to achieve oscillation.^{[8]} The low frequency gain is given by:
If the two capacitors are replaced by inductors and magnetic coupling is ignored, the circuit becomes a Hartley oscillator. In that case, the input impedance is the sum of the two inductors and a negative resistance given by:
In the Hartley circuit, oscillation is more likely for larger values of transconductance and larger values of inductance.
Interestingly, the above analysis also describes the behavior of the Pierce oscillator. The Pierce oscillator, with two capacitors and one inductor, is equivalent to the Colpitts oscillator.^{[9]} Equivalence can be shown by choosing the junction of the two capacitors as the ground point. An electrical dual of the standard Pierce oscillator using two inductors and one capacitor is equivalent to the Hartley oscillator.
The amplitude of oscillation is generally difficult to predict, but it can often be accurately estimated using the describing function method.
For the commonbase oscillator in Figure 1, this approach applied to a simplified model predicts an output (collector) voltage amplitude given by:^{[10]}
where is the bias current, and is the load resistance at the collector.
This assumes that the transistor does not saturate, the collector current flows in narrow pulses, and that the output voltage is sinusoidal (low distortion).
This approximate result also applies to oscillators employing different active device, such as MOSFETs and vacuum tubes.
